Optimal. Leaf size=247 \[ \frac{5 b c^2 \text{PolyLog}\left (2,-e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}-\frac{5 b c^2 \text{PolyLog}\left (2,e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{2 \pi ^2 \sqrt{\pi c^2 x^2+\pi }}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi c^2 x^2+\pi \right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi c^2 x^2+\pi \right )^{3/2}}+\frac{5 c^2 \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{\pi ^{5/2}}+\frac{5 b c^3 x}{12 \pi ^{5/2} \left (c^2 x^2+1\right )}+\frac{b c}{4 \pi ^{5/2} x \left (c^2 x^2+1\right )}+\frac{13 b c^2 \tan ^{-1}(c x)}{6 \pi ^{5/2}}-\frac{3 b c}{4 \pi ^{5/2} x} \]
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Rubi [A] time = 0.47513, antiderivative size = 325, normalized size of antiderivative = 1.32, number of steps used = 15, number of rules used = 10, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.385, Rules used = {5747, 5755, 5760, 4182, 2279, 2391, 203, 199, 290, 325} \[ \frac{5 b c^2 \text{PolyLog}\left (2,-e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}-\frac{5 b c^2 \text{PolyLog}\left (2,e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{2 \pi ^2 \sqrt{\pi c^2 x^2+\pi }}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi c^2 x^2+\pi \right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi c^2 x^2+\pi \right )^{3/2}}+\frac{5 c^2 \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{\pi ^{5/2}}+\frac{5 b c^3 x}{12 \pi ^2 \sqrt{c^2 x^2+1} \sqrt{\pi c^2 x^2+\pi }}-\frac{3 b c \sqrt{c^2 x^2+1}}{4 \pi ^2 x \sqrt{\pi c^2 x^2+\pi }}+\frac{b c}{4 \pi ^2 x \sqrt{c^2 x^2+1} \sqrt{\pi c^2 x^2+\pi }}+\frac{13 b c^2 \sqrt{c^2 x^2+1} \tan ^{-1}(c x)}{6 \pi ^2 \sqrt{\pi c^2 x^2+\pi }} \]
Antiderivative was successfully verified.
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Rule 5747
Rule 5755
Rule 5760
Rule 4182
Rule 2279
Rule 2391
Rule 203
Rule 199
Rule 290
Rule 325
Rubi steps
\begin{align*} \int \frac{a+b \sinh ^{-1}(c x)}{x^3 \left (\pi +c^2 \pi x^2\right )^{5/2}} \, dx &=-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{1}{2} \left (5 c^2\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x \left (\pi +c^2 \pi x^2\right )^{5/2}} \, dx+\frac{\left (b c \sqrt{1+c^2 x^2}\right ) \int \frac{1}{x^2 \left (1+c^2 x^2\right )^2} \, dx}{2 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}\\ &=\frac{b c}{4 \pi ^2 x \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{\left (5 c^2\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx}{2 \pi }+\frac{\left (3 b c \sqrt{1+c^2 x^2}\right ) \int \frac{1}{x^2 \left (1+c^2 x^2\right )} \, dx}{4 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{\left (5 b c^3 \sqrt{1+c^2 x^2}\right ) \int \frac{1}{\left (1+c^2 x^2\right )^2} \, dx}{6 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}\\ &=\frac{b c}{4 \pi ^2 x \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}+\frac{5 b c^3 x}{12 \pi ^2 \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}-\frac{3 b c \sqrt{1+c^2 x^2}}{4 \pi ^2 x \sqrt{\pi +c^2 \pi x^2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{2 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}-\frac{\left (5 c^2\right ) \int \frac{a+b \sinh ^{-1}(c x)}{x \sqrt{\pi +c^2 \pi x^2}} \, dx}{2 \pi ^2}+\frac{\left (5 b c^3 \sqrt{1+c^2 x^2}\right ) \int \frac{1}{1+c^2 x^2} \, dx}{12 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}-\frac{\left (3 b c^3 \sqrt{1+c^2 x^2}\right ) \int \frac{1}{1+c^2 x^2} \, dx}{4 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{\left (5 b c^3 \sqrt{1+c^2 x^2}\right ) \int \frac{1}{1+c^2 x^2} \, dx}{2 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}\\ &=\frac{b c}{4 \pi ^2 x \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}+\frac{5 b c^3 x}{12 \pi ^2 \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}-\frac{3 b c \sqrt{1+c^2 x^2}}{4 \pi ^2 x \sqrt{\pi +c^2 \pi x^2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{2 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{13 b c^2 \sqrt{1+c^2 x^2} \tan ^{-1}(c x)}{6 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}-\frac{\left (5 c^2\right ) \operatorname{Subst}\left (\int (a+b x) \text{csch}(x) \, dx,x,\sinh ^{-1}(c x)\right )}{2 \pi ^{5/2}}\\ &=\frac{b c}{4 \pi ^2 x \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}+\frac{5 b c^3 x}{12 \pi ^2 \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}-\frac{3 b c \sqrt{1+c^2 x^2}}{4 \pi ^2 x \sqrt{\pi +c^2 \pi x^2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{2 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{13 b c^2 \sqrt{1+c^2 x^2} \tan ^{-1}(c x)}{6 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{\pi ^{5/2}}+\frac{\left (5 b c^2\right ) \operatorname{Subst}\left (\int \log \left (1-e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{2 \pi ^{5/2}}-\frac{\left (5 b c^2\right ) \operatorname{Subst}\left (\int \log \left (1+e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{2 \pi ^{5/2}}\\ &=\frac{b c}{4 \pi ^2 x \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}+\frac{5 b c^3 x}{12 \pi ^2 \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}-\frac{3 b c \sqrt{1+c^2 x^2}}{4 \pi ^2 x \sqrt{\pi +c^2 \pi x^2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{2 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{13 b c^2 \sqrt{1+c^2 x^2} \tan ^{-1}(c x)}{6 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{\pi ^{5/2}}+\frac{\left (5 b c^2\right ) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}-\frac{\left (5 b c^2\right ) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}\\ &=\frac{b c}{4 \pi ^2 x \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}+\frac{5 b c^3 x}{12 \pi ^2 \sqrt{1+c^2 x^2} \sqrt{\pi +c^2 \pi x^2}}-\frac{3 b c \sqrt{1+c^2 x^2}}{4 \pi ^2 x \sqrt{\pi +c^2 \pi x^2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{6 \pi \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{a+b \sinh ^{-1}(c x)}{2 \pi x^2 \left (\pi +c^2 \pi x^2\right )^{3/2}}-\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right )}{2 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{13 b c^2 \sqrt{1+c^2 x^2} \tan ^{-1}(c x)}{6 \pi ^2 \sqrt{\pi +c^2 \pi x^2}}+\frac{5 c^2 \left (a+b \sinh ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{\pi ^{5/2}}+\frac{5 b c^2 \text{Li}_2\left (-e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}-\frac{5 b c^2 \text{Li}_2\left (e^{\sinh ^{-1}(c x)}\right )}{2 \pi ^{5/2}}\\ \end{align*}
Mathematica [A] time = 6.15641, size = 331, normalized size = 1.34 \[ \frac{-60 b c^2 \text{PolyLog}\left (2,-e^{-\sinh ^{-1}(c x)}\right )+60 b c^2 \text{PolyLog}\left (2,e^{-\sinh ^{-1}(c x)}\right )-\frac{48 a c^2}{\sqrt{c^2 x^2+1}}-\frac{8 a c^2}{\left (c^2 x^2+1\right )^{3/2}}-\frac{12 a \sqrt{c^2 x^2+1}}{x^2}+60 a c^2 \log \left (\pi \left (\sqrt{c^2 x^2+1}+1\right )\right )-60 a c^2 \log (x)+\frac{4 b c^3 x}{c^2 x^2+1}-\frac{48 b c^4 x^2 \sinh ^{-1}(c x)}{\left (c^2 x^2+1\right )^{3/2}}-\frac{56 b c^2 \sinh ^{-1}(c x)}{\left (c^2 x^2+1\right )^{3/2}}-60 b c^2 \sinh ^{-1}(c x) \log \left (1-e^{-\sinh ^{-1}(c x)}\right )+60 b c^2 \sinh ^{-1}(c x) \log \left (e^{-\sinh ^{-1}(c x)}+1\right )+6 b c^2 \tanh \left (\frac{1}{2} \sinh ^{-1}(c x)\right )-6 b c^2 \coth \left (\frac{1}{2} \sinh ^{-1}(c x)\right )-3 b c^2 \sinh ^{-1}(c x) \text{csch}^2\left (\frac{1}{2} \sinh ^{-1}(c x)\right )+104 b c^2 \tan ^{-1}\left (\tanh \left (\frac{1}{2} \sinh ^{-1}(c x)\right )\right )-\frac{6 b c \sinh ^{-1}(c x) \tanh \left (\frac{1}{2} \sinh ^{-1}(c x)\right )}{x}}{24 \pi ^{5/2}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.239, size = 314, normalized size = 1.3 \begin{align*} -{\frac{a}{2\,\pi \,{x}^{2}} \left ( \pi \,{c}^{2}{x}^{2}+\pi \right ) ^{-{\frac{3}{2}}}}-{\frac{5\,a{c}^{2}}{6\,\pi } \left ( \pi \,{c}^{2}{x}^{2}+\pi \right ) ^{-{\frac{3}{2}}}}-{\frac{5\,a{c}^{2}}{2\,{\pi }^{2}}{\frac{1}{\sqrt{\pi \,{c}^{2}{x}^{2}+\pi }}}}+{\frac{5\,a{c}^{2}}{2\,{\pi }^{5/2}}{\it Artanh} \left ({\sqrt{\pi }{\frac{1}{\sqrt{\pi \,{c}^{2}{x}^{2}+\pi }}}} \right ) }-{\frac{5\,b{x}^{2}{\it Arcsinh} \left ( cx \right ){c}^{4}}{2\,{\pi }^{5/2}} \left ({c}^{2}{x}^{2}+1 \right ) ^{-{\frac{3}{2}}}}-{\frac{b{c}^{3}x}{3\,{\pi }^{5/2} \left ({c}^{2}{x}^{2}+1 \right ) }}-{\frac{10\,b{\it Arcsinh} \left ( cx \right ){c}^{2}}{3\,{\pi }^{5/2}} \left ({c}^{2}{x}^{2}+1 \right ) ^{-{\frac{3}{2}}}}-{\frac{bc}{2\,{\pi }^{5/2}x \left ({c}^{2}{x}^{2}+1 \right ) }}-{\frac{b{\it Arcsinh} \left ( cx \right ) }{2\,{\pi }^{5/2}{x}^{2}} \left ({c}^{2}{x}^{2}+1 \right ) ^{-{\frac{3}{2}}}}+{\frac{13\,b{c}^{2}}{3\,{\pi }^{5/2}}\arctan \left ( cx+\sqrt{{c}^{2}{x}^{2}+1} \right ) }+{\frac{5\,b{c}^{2}}{2\,{\pi }^{5/2}}{\it dilog} \left ( cx+\sqrt{{c}^{2}{x}^{2}+1} \right ) }+{\frac{5\,b{c}^{2}}{2\,{\pi }^{5/2}}{\it dilog} \left ( 1+cx+\sqrt{{c}^{2}{x}^{2}+1} \right ) }+{\frac{5\,b{\it Arcsinh} \left ( cx \right ){c}^{2}}{2\,{\pi }^{5/2}}\ln \left ( 1+cx+\sqrt{{c}^{2}{x}^{2}+1} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{6} \, a{\left (\frac{15 \, c^{2} \operatorname{arsinh}\left (\frac{1}{\sqrt{c^{2}}{\left | x \right |}}\right )}{\pi ^{\frac{5}{2}}} - \frac{5 \, c^{2}}{\pi{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac{3}{2}}} - \frac{15 \, c^{2}}{\pi ^{2} \sqrt{\pi + \pi c^{2} x^{2}}} - \frac{3}{\pi{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac{3}{2}} x^{2}}\right )} + b \int \frac{\log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )}{{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac{5}{2}} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{\pi + \pi c^{2} x^{2}}{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}}{\pi ^{3} c^{6} x^{9} + 3 \, \pi ^{3} c^{4} x^{7} + 3 \, \pi ^{3} c^{2} x^{5} + \pi ^{3} x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \operatorname{arsinh}\left (c x\right ) + a}{{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac{5}{2}} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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